From regression analysis of an extended set of flow data at the reach, the follo

Question

From regression analysis of an extended set of flow data at the reach, the following power law relation was established between the mean flow velocity (U) at the cross section and the discharge:

U = kQm

where k = 0.108 and m = 0.398 (r2 = 0.89). Determine U for the low flow and bank full stages. Shade in the contour interval that most closely matches the mean flow at the cross section. Does this seem reasonable? Provide a brief interpretation.

Low flow Stage

k = 0.108

              Q= 35m3s-1

m = 0.398

U = kQm= (0.108)( 35m3s-1)0.398 = 0.44 m/s = 44 cm/s

Low flow Stage

k = 0.108

Q= 250m3s-1

m = 0.398

U = kQm= (0.108)( 250m3s-1)0.398 = 0.97 m/s = 97 cm/s

Please provide an interpretation.

Explanation / Answer

Seems reasonable.

The rate of flow is proportional to the mean flow velocity. The rate of flow for the same cross section can increase, only if the velocity increases.

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