From mypreivious questions, \"Confidence intervlas\" \"A researcher admnisistere

Question

From mypreivious questions, "Confidence intervlas"

"A researcher admnisistered a test of mathematical ability to asample of 169 students. The mean of the sample was 74.40. the standard deviation for the population,, was known to be 13.00. Compute the 95% and 99%confidence intervals." Assuming the population standard deviationfor my previous question was 7.00instead of 13.00. Computer the 95 % and 99%confidence intervlas. What is the effect of decresasing onthe width of the intervals? From mypreivious questions, "Confidence intervlas"

"A researcher admnisistered a test of mathematical ability to asample of 169 students. The mean of the sample was 74.40. the standard deviation for the population,, was known to be 13.00. Compute the 95% and 99%confidence intervals." Assuming the population standard deviationfor my previous question was 7.00instead of 13.00. Computer the 95 % and 99%confidence intervlas. What is the effect of decresasing onthe width of the intervals?

Explanation / Answer

95% ={73.34, 75.46}
99% - {73.01, 75.79}
A confidence interval uses the standard deviation to estimatea certain percentage of scores that falls within the confidenceinterval, and as the sd decreases, the interval decreases as thescores are more compact - and a larger percentage will fall withinthe same interval.

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