(11) A student studied the photoelectric effect from two different metals by per

Question

(11) A student studied the photoelectric effect from two different metals by performing two separate experiments. In the first experiment, using a light source where the frequency of the light can be varied, the student obtained the following plot of stopping potential versus frequency of incident photon for the two metals. The measured value of the factor "C" as shown in the plot was found to be 0.48936. In the second experiment, using a light source emitting light with only one wavelength, the student found that the magnitude of stopping potential for photoelectrons released from Sample A is 2.4 V largeir than that for Sample B. Identify Sample A and Sample EB 3 0.0 Cf Frequency of Photon (A) (B) (C) (D) (E) Sample A is Sodium and Sample B is Gold Sample A is Sodium and Sample B is Copper Sample A is Aluminum and Sample B is Silicon Sample A is Gold and Sample B is Aluminum Sample A is Carbon and Sample B is Sodium

Explanation / Answer

To solve this question i want to share some data of Work function of some elements (in eV)

Sodium = 2.28

Gold = 5.1

Copper = 4.7

Aluminum = 4.08

Silicon = 4.72

Carbon = 4.81

Now solution

As we see in the question that the stopping potential of two samples have difference of 2.4 V

Now we find the stopping potential of all the options available

A) Stopping potential of Gold - stopping potential of Sodium = 5.1-2.28 = 2.82 V

B) Stopping potential of Copper - Stopping potential of Sodium=4.7-2.28= 2.42 V

C) Stopping potential of silicon - Stopping potential of Aluminum = 4.72-4.08 = 0.64 V

D) stopping potential of Aluminum - Stopping potential of Gold = 4.08-5.1 =-1.02 V

E) Stopping potential of Sodium - Stopping potential of Carbon = 2.28 - 4.81 = -2.53 V

Here we can see that Option B is satisfying the stopping potential condition given in the question that Stopping potential of sample A is more then Stopping potential of Sample B by 2.4 V

Hence option B is the answer

As Stopping potential (V) = Work function / electronic Charge

Thanks

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