(11 %) Problem 1: A charged particle (q = 6.5x 10 10 C) experiences force of F =

Question

(11 %) Problem 1: A charged particle (q = 6.5x 10 10 C) experiences force of F = 3.5i-32J N in an electric field 50% Part (a) Write an expression for the electric field vector E to which the charge is subject, in terms of the force F. > X 50% Part (b) Assume this field is generated by a point charge of Q = 5 × 10-9 C. How far away is this charge located? Give your answer in meters Grade Summary Deductions Potential d= 3.342 * 10-171 1% 99% sin0 cotan asin) Submissions Attempts remaining: 9 (1 % per attempt) detailed view cosO tan() | | ( acosO 789HOME atan)acotan)sinh0 1% tanh) cotanh() 0 Co END °Degrees Radians OBACKSPACECLEAR Submit I give up! Hints: 2 for a 0% deduction. Hints remaining: 0 Feedback: 0% deduction per feedback -Calculate the magnitude of the force -Use Coulomb's Law to find the distance

Explanation / Answer

Electric field due due to Q,

E= F/q= (3.5i-3.2j )/(6.5*10-10)

E= (0.538i-0.492j)*1010

| E | = (0.5382+ 0.4922)0.5* 1010= 7.2925* 109

KQ/r2= 7.2925*109

9*109* 5*10-9/r2= 7.2925*109

r= 7.855*10-5 m

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