(10) In the figure below, the magnetic field intensity through the loop changes
ID: 1470621 • Letter: #
Question
(10) In the figure below, the magnetic field intensity through the loop changes from +0.562T (pointing out of the page) to -0 .423 T (pointing into the page) in 150ms. Shown below is the field at the end of this cycle (-.423 T). The radius of the single loop is .15cm and the resistance in the wire is 0.225 . (a) What is the magnitude of the emf induced in the loop? (b) What is the current in A at 2s? (c) Calculate the magnitude of the induced current. (c) In which direction is this current through the resistor? Left or Right
Explanation / Answer
Given,
B1 = 0.562 T
B2 = -0.423 T
time taken, t = 150 ms = 0.15 s
radius, r = 0.15 cm
Resiatnce, r 0.225 ohms
Area of the loop, A = pi*r^2
= pi*(0.15*10^-2)^2
= 7.07*10^-6 m^2
A) Induced emf = A*(B1-B2)/t
= 7.07*10^-6*(0.562 - (-0.423))/0.15
= 4.64*10^-5 volts
B) at t = 2s,
inuced current = 0
because there is no change in magnetic flux at this time.
C)
induced current = induced emf/R
= 4.64*10^-5/0.225
= 2.06*10^-4 A
D) Right
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