Evaluate the time constant of the circuit = RC = (8.4 × 105 )(4.30 F) 36000001 x
ID: 3308577 • Letter: E
Question
Evaluate the time constant of the circuit = RC = (8.4 × 105 )(4.30 F) 36000001 x s Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. Evaluate the maximum charge on the Q = CE = (4.30 F)(12.0 V) = 51.6 Evaluate the maximum current in the circuit 12.0 V 8.4 x 10 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. Find the charge and current as functions of time (in seconds): q()-E161c)( x ) (Use the following as necessary: .) /(r) = ( 0000143 x Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step c; (Use the following as necessary: t.)Explanation / Answer
time constant. T = R C
T = (8.4 x 10^5) (4.30 x 10^-6)
T = 3.612 s ...........Ans
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maximum charge , Q0 = C V = (4.30 uF) (12)
Q0 = 51.6 uC .....Ans
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Maximum curent, I0 = v / R = 14.3 x 10^-6 A Or 14.3 uA
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Q = Q0 [1 - e^(-t/T)]
Q = (51.6 uC) [ 1 - e^(-t/3.6)] .......Ans
I = (14.3 x 10^-6 A) [ e^(-t/3.6)]
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