Active Flgure 2.2-Position vs. Time Instructions: Use the following figure, whic

Question

Active Flgure 2.2-Position vs. Time Instructions: Use the following figure, which depicts a car moving forward and backward, and click "start" begin the exercise A car being driven along a straight road passes the point = 30 m at r = 0 toreach 18-50 m att- 10 seconds. Then it reaches xf -50 m att- 50 s. Find the average velocity, and average speed. (a) from to (b) from ® to D, and then (c) from S to . -30 -20 -10 10 30 50 60 x (m) xtm) We represent the motion of the car by the location of some part of it, such as the leading edge of the front bumper. Therefore the car is represented by a point moving along the x axis with positive values of x to the right and negative values the left. 40 F reset -60 10 20 30 50 t(s) Display in a New Window

Explanation / Answer

(a) Displacement or distance travelled x = 50 - 30 = 20m and T = 10 s

Average velocity = x/t = 20/10 = 2 m/s

Average speed = x/t = 20/10 = 2 m/s

(b) Distance travelled = 100m. Displacement = -50 -50 = -100m. Time taken = 50-10 = 40s

Average velocity = x/t = -100/40 = -2.50 m/s

Average speed = x/t = 100/40 = 2.50 m/s

(c) Distance travelled = 20 + 100 = 120 m. Displacement = -50 -30 = -80m. Time taken = 50-0 = 50s

Average velocity = x/t = -80/50 = -1.60 m/s

Average speed = x/t = 120/50 = 2.40 m/s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.