Electrons Up quark 4. Hubble\'s Law relationship between redshift and distance,

Question

Electrons Up quark 4. Hubble's Law relationship between redshift and distance, coupled with a supposed linear relation of the linear recessional velocity and redshift, yields a straightforward mathematical expression for Hubble's Law as The d follows: Where v is the recessional velocity, typically expressed in km/s Ho-71 km s,Mpc., is Hubble's constant and corresponds to the value of H(often termed the Hubble parameter which is a value that is time dependent and which can be expressed in terms of the scale factor). d is the proper from the galaxy to the observer, measured in mega parsecs (Mpc . . · * 2000 M,-68 km/s Mpc 1000 Virgo Cluster 10 Distance (Mpc) 20 Page 5 of e 4.1 Express the Hubble constant in units of l/sec 42 lfadistant galaxy has a speed-=0.02, where c is the specd oflight, how far is the object?

Explanation / Answer

4.1

We have,

H0 = 71 km/s Mega Parsec

1 Parsec = 3.26 LY

The light in 1 year travels,

d = 3 x 10^8 x 60 x 60 x 24 x 365.25 = 9.47 x 10^15 m

1 Parsec = 9.47 x 10^15 x 3.26 = 3.086 x 10^16 m

1 Mpc = D = 3.086 x 10^22 m

H0 = v/D = 71000/3.086 x 10^22 = 2.3 x 10^-18 s

Hence, H0 = 2.3 x 10^-18 s

4.2

v/c = 0.02 => v = 6 x 10^6 m/s

v = H0 d

d = v/H0 = 6 x 10^6/(2.3 x 10^-18) = 2.61 x 10^24m

Hence, d = 2.61 x 10^24 m

Related Questions

Navigate

• Browse (All)
• Browse E
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.