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Electrons (electron 1.6E-19) are moving through a conductor from right to left a

ID: 2032951 • Letter: E

Question

Electrons (electron 1.6E-19) are moving through a conductor from right to left at 20cm/s (as shown in the figure). The conductor (thickness ? 4mm) sits inside a homogeneous magnetic field of 0.IT which is perpendicular to the direction of motion of the electrons. The magnetic force deflects the electrons to the bottom of the conductor which establishes an electric fields (and hence an emf) between the bottom and the top of the conductor. In addition to the magnetic force the electron now also start to feel the effects of the rising electric force. At the point where the electric force equals the magnetic force a maximum emf (the so-called Hall emf) is reathed. Bou Calculate the Hall emf? What is the direction of motion of the electrons once the Hall emf is reached?

Explanation / Answer

Given,

B= 0.1 T

l = 4mm = 0.004 m

v= 20cm/s = 0.2m/s

Hall emf = B*l*v = 0.1 * 0.004 * 0.2 = 0.00008 V

Electrons travel from right to left when hall emf is reached.

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