v as a function of frequency ?need help making sense of this question. is it tel

Question

v as a function of frequency ?need help making sense of this question. is it telling me that f= v_out/v_max, or that (v_out/v_max) = .9, .8 , ....

D. Characterize the shape of the resonance by measuring Vout or several ("20) frequencies around fo. Au fo that yield Vou/max 0.9, 0.8,...0.1. Plot 2o*log[VoudVmax) idB) as a function of frequency (kHz). Obtain an experimental value for the quality factor: O-To/ Ay sdB where Afads, is difference between the two frequencies where the power is half its maximum value Vma/v2. For maximum accuracy you should linearly interpolate between data points, or fit the maximum to a quadratic function. (peak-to-peak) as a function of frequency take data is to find frequencies above and below

Explanation / Answer

in this question you are asked to plot Vout as a function of frequency, Since the output must be a function of frequency as well as input voltage, you have to expressed the output Vout in term of maximum out put voltage Vmax as well as in put frequency and then plot Vout vs f in log scale. I think this is relating to BJT or Filtering or frequency response question.

Thank you

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