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An instructor is evaluating the performance of students on a test. He records th

ID: 3305035 • Letter: A

Question

An instructor is evaluating the performance of students on a test. He records the number of points that each student missed and created a frequency distribution. This is provided below: Points missed 0-under 10 number of students 2 10-under 20 number of students 6 20-under 30 number of students 8 30-under 40 number of students 12 40-under 50 number of students 6
What is the median for this population? a. 19.43 b. 26.14 c. 27.34 d. 28.17 *e. 30.83

An instructor is evaluating the performance of students on a test. He records the number of points that each student missed and created a frequency distribution. This is provided below: Points missed 0-under 10 number of students 2 10-under 20 number of students 6 20-under 30 number of students 8 30-under 40 number of students 12 40-under 50 number of students 6
What is the median for this population? a. 19.43 b. 26.14 c. 27.34 d. 28.17 *e. 30.83

An instructor is evaluating the performance of students on a test. He records the number of points that each student missed and created a frequency distribution. This is provided below: Points missed 0-under 10 number of students 2 10-under 20 number of students 6 20-under 30 number of students 8 30-under 40 number of students 12 40-under 50 number of students 6
What is the median for this population? a. 19.43 b. 26.14 c. 27.34 d. 28.17 *e. 30.83

Explanation / Answer

Since there are 34 values, the median is the average of the 17th and 18th values both of which lie in the 30-40 group.

Median = L + ((n/2) - B)/G) W

L = 29.5 n = 34 B = 2 + 6 + 8 = 16 G = 12 W = 10

=> Median = 30 + ((34/2) - 16)/12) * 10

= 30.83

0-10 10-20 20-30 30-40 40-50 2 6 8 12 6
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