The load life X was measured (in millions of revolutions) for 80 ceramic ball be
ID: 3304127 • Letter: T
Question
The load life X was measured (in millions of revolutions) for 80 ceramic ball bearings subjected to a 6.45kN load. A summary of the data from JMP is on the next page. 1. a) The load life needs to average more than 150 for bearings of this type. Is there sufficient evidence to justify this claim? Explain fully, showing all parts of a hypothesis test, with 0.01 significance level. b) What do the normal diagnostic plot (Q-Q plot) and Shapiro-Wilk's test indicate about distribution of X, in terms of shape, symmetry, etc.? Is a normal distribution plausible? c) Use the delta method to approximate SE(X1/3) Summary Statistics Goodness-of-Fit Test Shapiro-Wilk W Test 175.6242 86.28983 Std Dev W 0.921522 P-Value 0.0001 445.9349 10461532 10105432 49.133224 62.52666 450.14769 158.04947 CV Normal Diagnostic Plot 500 450 400 350 300 250 200 150 100 50 0.015 0.05 009 0.16 03 0.5 0.7 084 091 0.95 Normal ProbabilityExplanation / Answer
Solution1A:
From summary we can conclude that mean>median
load life is positively skewed
Test for Hypothesis of single mean:
State null and alternative hypothesis.
Null hypothesis
H0: mean=150
Alternative Hypothesis:
H1:mean>150
alpha=0.01
calculation of test statistic:
Given sample mean=xbar=175.6242
sample sd=86.289831
sample size=n=80
t=175.6242-175/86.289831/sqrt(80)
t=0.065
Calculation of p value
Degrees of freedom=n-1=80-1=79
alpha=0.01
P value=0.474169
p>0.01
Decsion:
p>0.01 fail to reject null hypothesis
Accept Null hypothesis
Conclusion:
there is no sufficient evidence at 1% level of significance to conclud that average more than 150
Solutionb:
From normal probablilty plot
normal probability plot is formed by
vertical axis:load life
horizontal axis :normal order statistic medians
The points on this plot form a does not form nearly linear pattern,which indicates not a normal d
there are outliers.istribution
Shapiro test:
H0:samples come form normal distribution
H1:samples do not come form normal distribution
test statistic:0.9215
p<0.01
Reject Null hypothesis
does not follow normal distribution
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