Please help me.. it is urgent. In a test of the effectiveness of garlic for lowe

Question

Please help me.. it is urgent.

In a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes in their levels of LDL cholesterol (in mg/dL) have a mean of 4.6 and a standard deviation of 16.1. Complete parts (a) and (b) below Click here to view a t distribution table of the standard normal distribu of the standard normal distribution tabl a. What is the best point estimate of the population mean net change in LDL cholesterol after the garlic treatment? The best point estimate is mg/dL (Type an integer or a decimal.) b. Construct a 90% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? What is the confidence interval estimate of the population mean ? mg/dL

Explanation / Answer

(a)

The best point estimate is 4.6 mg/dL

(b)

t-value for 90% CI, 1.6779 (here t value is used as population sigma is not known, one can also solve this using z value = 1.65)

Margin of Error ME = t * s/sqrt(n) = 1.6779 * 16.1/sqrt(48) = 3.8992

lower bound = 4.6 - 3.8992 = 0.7008

upper bound = 4.6 + 3.8992 = 8.4992

CI, 0.7008 < mu < 8.4992

The confidence interval limits do not contain 0, suggesting that the garlic treatment did not affect the LDL cholesterol levels (option C)

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