Please help me, Please show me detailed solution At t=0 panicle is at rest x = 2

Question

Please help me, Please show me detailed solution

At t=0 panicle is at rest x = 2m. After its release it can move under influence of conservative force whose potential energy is shown in the diagram. What is the total energy of the particle at x=8m What is the position of the right turning point for this particle what is the kinetic energy of the particle at 10m? The skier of mass M slides from on an icy (frictionless) hemispherical mountain of radius R. Draw the free body diagram, and write Newton's Second Law for the block of mass it is at some point on the slope At what angle alpha with vertical will she loose contact with the surface ?

Explanation / Answer

so total energy = KE + Pe
since at rest at x=2

KE = U(x=2) = 4 J

b) turns right at x=12m

c) at x-10 U = 3 J

so Ke = 1 J

5)
a)
mg down and N up and to the right

b) at an angle alpha

conservation of energy
M g R = 1/2 mv^2 + M g R cos alpha
v^2 = 2 g R (1- cos alpha)

forces
m g cos alpha - N = mv^2/r
if loses contact N = 0

m g cos alpha = mv^2/r
plug in from energy
g cos alpha = 2 g ( 1 - cos alpha)

cos alpha = 2 - 2 cos alpha

cos alpha = 2/3

alpha = 48.19 degrees

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.