in a test of the efectiveness of ark foIo em cholesterol 44 sutpects were treate
ID: 3298892 • Letter: I
Question
in a test of the efectiveness of ark foIo em cholesterol 44 sutpects were treated with gar c un a processed tablet form Cholesterol levels were measured before and ater the treatment The changes in their levels of LDL cholestesol (in mgidL) have a mean of 5.7 and a standard deviation of 19 4 Complete parts (a) and (b) below cack here to vew a.ldistnbution tabile a.vnan sthe best pont estimate ofthe pogutation mean net change LDL cholesterol arene garlic treatment? The test point estimate is I lmgo (Type an integer or a decimal y b.Construct a 99% confidence interval estimate of the mean net change n LDL cholesterol aner he garic ,ea ment what does te coterce itena suggest about ehdenes d gar n marg what is tre contence rterval estm ate of the population mean ?Explanation / Answer
a) The best point estimate is 5.7 mg/dL
b)
mean = 5.7
std. dev. = 19.4
n = 44
For 99%, z-value = 2.58
Margin of Error, ME = 2.58*19.4/sqrt(44) = 7.5456
Lower bound = 5.7 - 7.5456 = -1.8456
Upper bound = 5.7 + 7.5456 = 13.2456
Interval will be -1.8456 < mu < 13.2456
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