Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

please answer all parts and type them vincent ? secure https://www.mathxl.com St

ID: 329813 • Letter: P

Question

please answer all parts and type them

vincent ? secure https://www.mathxl.com Student PlayerHomework.aspx?homeworkld=472996154&questionid-11;&flushedstrue;&cld-4912944;& ? ? e ? e G MANAGEMENT OF OPERATIONS (1) Vincent Amoia 4/13/18 10:25 PM Homework: Homework 6 Score: 0 of 1 pt Problem 12.4 Save 9 of 14 (11 complete)> Hw Score: 76.79%, 10.75 of 14 pts Question Help Lindsay Electronics, a small manufacturer of electronic research equipment, has approximately 7,000 items in its inventory and has hired Joan Blasco Paul to manage its inventory. Joan has determined that 12% of the items in inventory are A items, 37% are B items, and 51% are C items. She would like to set up a system in which all A items are counted monthly every 19 working days all B items are counted quarterly every 59 working days), and all C items are counted semiannually (every 121 working days). How many items need to be counted each day? The total number of items that need to be counted each day isitems (round your response to the nearest whole number) Enter your answer in the answer box and then click Check Answer. All parts showing Clear All Check Answer LawDepot-Rental L doc Rental-Lease Agree pdf |?Chapt 9 Making inve ppt … gbcconstitution.09.docx Show All …

Explanation / Answer

To be calculated:

Total number of items that need to be counted each day

Given values:

Total items in inventory = 7,000

A items in inventory = 12% = 0.12

B items in inventory = 37% = 0.37

C items in inventory = 51% = 0.51

Item A = counted every 19 working days

Item B = counted every 59 working days

Item C = counted every 121 working days

Solution:

A items in inventory = 0.12 x 7000 = 840

B items in inventory = 0.37 x 7000 = 2,590

C items in inventory = 0.51 x 7000 = 3,570

Total number of items that need to be counted each day is calculated as;

A = 840 / 19 = 44.21

B = 2590 / 59 = 43.90

C = 3570 / 121 = 29.50

Total number of items counted each day = 44.21 + 43.90 + 29.50

Total number of items counted each day = 117.61 or 118 (rounding off to nearest whole number)

Total number of items counted each day = 118 items