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A genetic experiment involving peas yielded one sample of offspring consisting o

ID: 3297038 • Letter: A

Question

A genetic experiment involving peas yielded one sample of offspring consisting of 443 green peas and 179 yellow peas. Use a 0 05 significance level to test the claim that under the same circumstances, 26% of offspring peas will be yellow. Identify null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. A. H_0: p notequalto 0.26 H_1: p 0.26 C. H_0: p notequalto 0.26 H_1: p = 0.26 D. H_0: p = 0.26 H_1: p > 0.26 E. H_0: p = 0.26 H_1: p notequalto 0.26 F. H_0: p = 0.26 H_1: p

Explanation / Answer

option E) is correct

X = 179, n = 443

p^ - X/n = 179/443 = 0.4040632

TS = (p^ - p)/sqrt(pq/n)

= (0.4040632- 0.26)/sqrt(.26 *0.74 / 443)

= 6.9127744

p-value = 2 P(Z >6.9127744)

= 0.0000

since p-value < 0.05 ,we reject the null hypothesis , option A) is correct

final conclusion

option C) is correct

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