It\'s the same question but I had to add the other information. Thank you. 6.56

Question

It's the same question but I had to add the other information. Thank you. 6.56 In the service garage of a large automobile dealer, customers spend the following amounts, during each visit, for maintenance and repair of their motor vehicles Distributions Dollars Less than $200 $200 but less than $400 $400 or more Percentage of customers 40 40 20 What is the probability that on a certain day, among six randomly selected customers, three will spend less than $200, two will spend $200 and under $400,an one will spend $400 or more?

Explanation / Answer

The required probability is:

P = W*0.43*0.42*0.2

Here W is the multiplicity.

For this case, W = (6!)/(3!*2!*1!) = 60

So,

P = 60*0.43*0.42*0.2 = 0.123

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.