PLEASE ANSWER ANY OF THE QUESTIONS BELOW, I WILL EVENTUALLY NEED THEM ALL ANSWER
ID: 3292883 • Letter: P
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PLEASE ANSWER ANY OF THE QUESTIONS BELOW, I WILL EVENTUALLY NEED THEM ALL ANSWERED 0 Find the a scone Sor each alene and dhoose the corect statement Me .46 | 50 · 5 Dall work on the scratch paper provided. DONOT write on this test booklet. Record you 2. Which of the following statements correctly describes the relationship between a sample and a population? #5 a) A sample is a group of populations that are subject to observation. b) A population is a group of samples that may or may not be included in a study. c) A sample is a group of subjects selected from a population to be studied. d) A population and a sample are not related 11 345589 The rang of the grades is berween 98 and 23 biOf e 29 dsho sook the esam, 9of them scored betwees 80 and 89 2 Given the llowing bo plet where m is the medvaue, what sanement could be The amount of time needed to run the Boston marathon is an example of which type of variable? a) discretc b) categorical c) continuous d) none of the above 13 Gia n ninayck of cards wha is the probability thar a single drawn cand 17. Give the mean of the following probabilityistribution Plz) 02 a) 1.20 b) 146 c) 3.15 4) 213 35 0.0 03 18 What is the standard deviation of the following probability distribution? 14 Agam ball machine contains 300gcapolavored bals, 400 derry flavoredbals nd 500 lemon flavored balls. What is the probabity ofgotting grape bal, chery tul and I lemon ball if cnly three balls are removed from the machine? Pz) 02 005 035 02 b) 4.7 a) 00264 b) 00531 c) 0.0348 d) 00482 c)54 d)26 25 Asample of25 áles payfull depannets found that the 1oyees worked an average of31° 3 days a year with a ta deviation of23 8 days. The standard 15, A recent poll by the American Automobile abfound that 30% ofthose sneyed are worried about aggressive drivers on the road. If 3 people are selected at random what is the probability that all 3 will be worried about aggressive drivers on the roa? iatioofor allemployees snot know, w the 90% coefdence inter al for the average days worked pofall payroill departments? #random what dei a)301.0Explanation / Answer
17)
mean = 1 * 0.2 + 2 * 0.1 + 3 * 0.35 + 4 * 0.05 + 5 * 03
= 3.15
answer is option c)
18)
mean = 0 * 0.2 + 2 * 0.05 + 4 * 0.35 + 6 * 0.25 + 8 * 0.35
= 5.8
standard deviation = ( 0 - 5.8)^2 * 0.2 + ( 2 - 5.8)^2 * 0.05 + (4 - 5.8)^2 * 0.35 + ( 6 - 5.8)^2 * 0.25 + ( 8 - 5.8)^2 * 0.35
= 3.207
Option is not given.
25)
mean = 310.3 , s = 23.8 , n =25
z value at 90% CI = 1.645
CI = mean + /- z * ( s/sqrt(n))
= 310.3 + /- 1.645 * ( 23.8 / sqrt(25))
= (302.469 , 318.130)
answer is option c)
26)
mean = 13.8 , s = 7.3 , n =45
z value at 99% CI = 2.576
CI = mean + /- z * ( s/sqrt(n))
= 13.8 + /- 2.576 * ( 7.3 / sqrt(45))
= (10.996 , 16.603)
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