1. How many degrees of freedom are there for factors A and B? ( a -2,3 b -3,4 c
ID: 3292249 • Letter: 1
Question
1. How many degrees of freedom are there for factors A and B? ( a -2,3 b -3,4 c - 2,4 d -3,6 )
2. Which of the following is the value of the test statistic for factor A? ( a - 5.14 b - 32.86 c - 4.76 d - 9.41 )
3. At the 5% significance level, the critical value for the hypothesis test about factor A is ________. (a - 5.14 b - 7.26 c- 10.92 d - 3.46 )
4. At the 5% significance level, the conclusion for the hypothesis test about factor A is ________.
(a -reject the null hypothesis; we cannot conclude the average mortgage payments differ by income level
b - do not reject the null hypothesis; we cannot conclude the average mortgage payments differ by income level
c - do not reject the null hypothesis; the average mortgage payments differ by income level
d - eject the null hypothesis; the average mortgage payments differ by income level)
Income (Factor A) Medium Low 25 70 30 High Zonal Location (Factor B) Downtown 60 75 35 25 Midtown 40 Uptown 30 Source of Variation df MS Rows (Factor B) 1 1,985.42 11,137.50 Columns (Factor A) Error Total 7,456.25Explanation / Answer
following information has been generated,
(a) since level of factor A and B are 3 and 4 respectively so its degree of freedom(df) will be 3-1=2 and 4-1=3
right choicei is a - 2,3
(2) SS for factor B=df(B)*SS(B)=3*1985.42=5956.26,
Error(SS)=Total SS - SS(A)-SS(B)=7456.25-5956.26-1137.5=362.49
MS=SS/df
test statistic for factor A is givne as F=MS(A)/MS(error)=568.75/60.415=9.41
right choice is d=9.41
(3) critical F(0.05,2,6)=5.14 ( using ms-excel command =FINV(0.05,2,6) )
(4) since critical F=5.14 is less than test statistic F for factor A =9.41, so we reject H0
right choice is d - reject the null hypothesis; the average mortgage payments differ by income level)
Source of variation SS df MS F Rows(Factor B) 5956.26 3 1985.42 3.490848 Columns (Factor A) 1137.5 2 568.75 9.414053 Error 362.49 6 60.415 Total 7456.25 11Related Questions
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