1. How large (in kg) an oxygen candle (KClO3) would be needed to supply 8 people

Question

1. How large (in kg) an oxygen candle (KClO3) would be needed to supply 8 people with enough oxygen for 24 hours on a small submarine. The average person needs .84 kg of O2 per day.

2. At 1 atmosphere and 25 degrees celcius what would the volume of 02 be from the previous question?

3. Assuming that the air is 21% O2 by volume, what volume of air would be needed to answer question 2?

4. assuming all of the analogous reactions occur, why would lithium chlorate be a more practical choice for the "chlorate candle" than either sodium or potassium chlorate.

Explanation / Answer

The average person needs .84 kg of O2 per day=

8people==>0.84*8=6.72 kg of O2 per day

an oxygen candle (KClO3) would be needed =[122.5/48] *6.72=17.15kg

2)

PV=nRT

V=nRT/P=[17.15*1000/16]8.314*298 /1 =26.55*10^5L

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.