The mean daily production of a herd of cows is assumed to be normally distribute

Question

The mean daily production of a herd of cows is assumed to be normally distributed with a mean of 38 liters, and standard deviation of 10.7 liters A) What is the probability that daily production is between 52.4 and 57.9 liters? Do not round until you get your your final answer. O(Round your answer to 4 Answer decimal places.) Warning: Do not use the Z Normal Tables...they may not be accurate enough since WAMAP may look for more accuracy than comes from the table. License Points possible: 10 This is attempt 1 of 2. Message instructor about this question Submit

Explanation / Answer

Q1) P(52.4<X<57.9)

= P((52.4-38)/10.7<Z<(57.9-38)/10.7)

= P(1.346<Z<1.860)

= 0.0577

Q2) P(X>77)

= P(Z>(77-78.8)/9.1)

= P(Z>-0.1978)

= 0.5784

Q3) a) Score =(680-515)/82 = 2.012

b) Score = (27-23)/3.5 = 1.143

c) Gerald. Option A is Correct

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