As shown in figure the store is to have .A timber floor which is supported by 10
ID: 3282715 • Letter: A
Question
As shown in figure the store is to have .A timber floor which is supported by 10 bearers (beams) 295 mm x 80 mm . The bearers selected are of machine graded sawn, unseasoned Grey Ironbark . The bearers have a clear span of 3.5m and the ends of the bearers sit on 100 mm . The compression flange of the bearers are restrained by joists at 450mm centers . The spacing between bearers is 2.4 metres. (depth x width) (Strength group S1, Stress grade F17) wide supports. (Hint: Lay 450mm) The live load applied along the length of the bearer has been calculated to be 3.0kN/m. The dead load applied along the length of the bearer, including self- weight has been calculated to be is 1.5kN/m . standards in Check the adequacy of the bearers to the requirements of relation to (a) bending strength, (b) shear strength, (c) bearing strength, and (d) imiting deflection Show all assumptions, formula, references and diagrams Lay 450 mm Bearer 95mm x 80mmm 100 mm 3500 mm 2400 mm 2400 mm 100 mm Figure 2 (not to scale)Explanation / Answer
There are really two factor that control manner strength.
Pull/Tear out 2. Bearing deformation How to compute each:
1. FailForce = ShearStrength MaterialThickness Length OfTear Out
2. FailForce = CompresiveStrength MaterialThickness RivetDiameter This assumes your rivet fills the hole completely. In addition, I wouldn't use this for a single lap joint.
The lap joint will twist and the failure will occur significantly below the above formulas. Instructions 1 Set up the algebraic equation: bearing stress (BS) = F/A. In this equation, F stands for how much force exists between the two contacting objects.
If you are using SI units, the determine of force is in Newtons. In the U.S., use pounds to designate the degree of force. The other factor of the equation is A, or the surface area where the two objects make contact. In SI units, use square meters to measure the area. In U.S. units, use square inches for the measurement. 2 Insert the measurement of force (F) into the equation. For example; if the force internally exerted between two objects is 10 lbs., your equation becomes BS = 10/A
. 3.Insert the area measurement into the equation. Using the same example; if the area is 2 square inches, the equation becomes BS = 10/2.
4 Divide the force (F) by the area (A) to solve for bearing stress (BS). Continuing the same example; this results in 5 lbs. per square inch, or 5 psi. If, in this example, SI units are used, the end result is 5 Newtons per square meter, or 5 Pasquals.
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