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·?R sign In l MasteringPhysics-M wileyPLUS KO nhttps/edugen.wileyplus.com/ed To see favorites here, select then ?, and drag to the Favorites Bar folder. Or import from another browser. Import favorites Home Read, Study& Practice AssignmentOpen Assignment × Ng wileyplus.com we Log In to Canvas uni Gradebook ORION Downloadable eTextbook ASSIGNMENT Chapter 16, Problem 010 The equation of a transverse wave traveling along a very long string is y-3.06 sin(0.0348TX+ 6.10?), where x and y are expressed in centimeters and t is in seconds. Determine (a) the amplitude, (b) the wavelength, (c) the frequency, (d) the speed, (e) the direction of propagation of the wave and (f) the maximum transverse speed of a particde in the string. (g) What is the transverse displacement atx 2.63 cm when t 0.147 s? hapter 16, Probl (a) Number (b) Number (c) Number (d) Number Units Units Units 037 040 (f) Number Units iew Results (g) Number Units SHOW HINT LINK TO TEXT Activate w Go-te Settings to Question Attempts: Unlimited SAVE FOR LATER SUBMIT 6:57 AM O Type here to search R 40 23-Apr-18 ^Explanation / Answer
compare the given equation with
y = A*sin(k*x + w*t)
a) Amplitude, A = 3.06 cm
b) k = 2*pi/lamda
lamda = 2*pi/k
= 2*pi/(0.0348*pi)
c) f = w/(2*pi)
= (6.10*pi)/(2*pi)
= 3.05 hz
d) v = w/k
= 6.10*pi/(0.0348*pi)
= 175.28 cm/s
e) Vmax = A*w
= 3.06*6.10*pi
= 58.61 cm/s
f)
y = 3.06*sin(0.0348*pi*2.63 + 0.0699*p*0.147)
Calculate by using the above formulas.
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