A diver 1.7 meters tall runs along a springboard with a speed of 7.2 meters per

Question

A diver 1.7 meters tall runs along a springboard with a speed of 7.2 meters per second. When she reaches the end of the board, she exerts X newtons of force on the board at a 60 degree angle. The rebound of the springboard propels the diver upward and forward while her body stays vertical. Just as she stops rising, she catches a ball thrown in the direction opposite to her motion at that moment. At the moment she catches it, the ball is moving horizontally at X centimeters per second and has no vertical velocity component. The water level is X centimeters below the springboard. The ball has a mass of 4.4 kilograms. The diver has a mass of 50 kilograms.

[e] If the diver catches the ball at her torso, and all the momentum of the ball is transferred into the horizontal motion of the diver and the ball, how far away horizontally from the end of the board will the diver be when she reaches the water?

Where x = 630 A diver 1.7 meters tall runs along a springboard with a speed of 7.2 meters per second. When she reaches the end of the board, she exerts X newtons of force on the board at a 60 degree angle. The rebound of the springboard propels the diver upward and forward while her body stays vertical. Just as she stops rising, she catches a ball thrown in the direction opposite to her motion at that moment. At the moment she catches it, the ball is moving horizontally at X centimeters per second and has no vertical velocity component. The water level is X centimeters below the springboard. The ball has a mass of 4.4 kilograms. The diver has a mass of 50 kilograms.

[e] If the diver catches the ball at her torso, and all the momentum of the ball is transferred into the horizontal motion of the diver and the ball, how far away horizontally from the end of the board will the diver be when she reaches the water?

Where x = 630 A diver 1.7 meters tall runs along a springboard with a speed of 7.2 meters per second. When she reaches the end of the board, she exerts X newtons of force on the board at a 60 degree angle. The rebound of the springboard propels the diver upward and forward while her body stays vertical. Just as she stops rising, she catches a ball thrown in the direction opposite to her motion at that moment. At the moment she catches it, the ball is moving horizontally at X centimeters per second and has no vertical velocity component. The water level is X centimeters below the springboard. The ball has a mass of 4.4 kilograms. The diver has a mass of 50 kilograms.

[e] If the diver catches the ball at her torso, and all the momentum of the ball is transferred into the horizontal motion of the diver and the ball, how far away horizontally from the end of the board will the diver be when she reaches the water?

Where x = 630

Explanation / Answer

u = 7.2 m/s

Total mass of the system = (50+4.4) = 54.4 kg

So, initial momentum = 54.4*7.2 = 391.68 kg-m/s

Given that the momentum will be transferred to the horizontal motion.

final velocity = 630 m/sec = 6.3 m/s

final momentum = 342.72 kg m/s

So, Scos60 = change in momentum

= 391.68-342.72

so,. S cos 60 = 48.96

S = 97.92 m

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