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A diver accustomed to standard snorkel tubing of length 25 cm tries a self-made

ID: 1480124 • Letter: A

Question

A diver accustomed to standard snorkel tubing of length 25 cm tries a self-made tube of length 8 m. During the attempt, what is the pressure difference between the external pressure on the diver's chest and the air pressure in the diver's lungs? (Assume the diver is in a fresh water lake with density P = 1.0 g/cm^3.) What happens to the diver as a result of the attempt? The diver's lungs will over-inflate due to the pressure difference. The diver's lungs will collapse due to the pressure difference. The diver's lungs will maintain normal functionality.

Explanation / Answer

pressure difference = density x g x h

= 1000 x 9.8 x 8 = 78400 Pa

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