A uniformly charged insulating sphere of radius 5.0 cm is fixed at the origin. A

Question

A uniformly charged insulating sphere of radius 5.0 cm is fixed at the origin. A conducting shell with inner radius 8.0 cm and outer radius of 11.0 cm is concentric with the sphere. The charge on the sphere is -5.5 uC and the excess charge on the shell is +2.4 uC. Find the electric field at 3.0 cm, 6.0 cm, 9.0 cm, and 12.0 cm from the origin and find the charge on both of the inner surface and the outer surface of the conducting shell. A uniformly charged insulating sphere of radius 5.0 cm is fixed at the origin. A conducting shell with inner radius 8.0 cm and outer radius of 11.0 cm is concentric with the sphere. The charge on the sphere is -5.5 uC and the excess charge on the shell is +2.4 uC. Find the electric field at 3.0 cm, 6.0 cm, 9.0 cm, and 12.0 cm from the origin and find the charge on both of the inner surface and the outer surface of the conducting shell.

Explanation / Answer

Here ,

as the electric field inside conducting shell is zero

also , the charge on the inside surface of the conducting shell is equal and oposite to the charge inside the shell

Now, for electric field

at r = 3 cm

electric field = 9*10^9 * (5.5 *10^-6 * 0.03)/0.05^3

electric field = 1.19 *10^7 N/C

at r = 6 cm

electric field = 9*10^9 * (5.5 *10^-6)/0.06^2

electric field = 1.375 *10^7 N/C

at r = 9 cm

inside the conducting shell , electric field is zero

at r = 12 cm

electric field = 9*10^9 * (-5.5 *10^-6 + 2.4 *10^-6 )/0.12^2

electric field = 1.94 *10^6 N/C

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