On the Apollo 14 mission to the moon, astronaut Alan Shepard hit a golf ball wit

Question

On the Apollo 14 mission to the moon, astronaut Alan Shepard hit a golf ball with a golf club improvised from a tool. The free-fall acceleration on the moon is 1/6 of its value on earth. Suppose he hit the ball with a speed of 31 m/s at an angle 22 above the horizontal. A) How long was the ball in flight? B) How far did it travel? C) Ignoring air resistance, how much farther would it travel on the moon than on earth? On the Apollo 14 mission to the moon, astronaut Alan Shepard hit a golf ball with a golf club improvised from a tool. The free-fall acceleration on the moon is 1/6 of its value on earth. Suppose he hit the ball with a speed of 31 m/s at an angle 22 above the horizontal. A) How long was the ball in flight? B) How far did it travel? C) Ignoring air resistance, how much farther would it travel on the moon than on earth? On the Apollo 14 mission to the moon, astronaut Alan Shepard hit a golf ball with a golf club improvised from a tool. The free-fall acceleration on the moon is 1/6 of its value on earth. Suppose he hit the ball with a speed of 31 m/s at an angle 22 above the horizontal. A) How long was the ball in flight? B) How far did it travel? C) Ignoring air resistance, how much farther would it travel on the moon than on earth?

Explanation / Answer

Gravity, g = 9.8/6 = 1.633

a) Time, t = 2 Vo sin(A)/g

t = 2 x 31 x sin(22)/1.633 =14.22 sec

b) distance, d = Vo cos(A) x t = 31 x cos(22) x 14.22 = 408.80 m

c) it would have travelled 6 times less (i.e. 408.80/6 = 68.13 m) on earth

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