On the Apollo 14 mission to the moon, astronaut Alan Shepard hit agolf ball with

Question

On the Apollo 14 mission to the moon, astronaut Alan Shepard hit agolf ball with a golf club improvised from a tool. The Free-fallacceleration on the moon is 1/6 of its value on earth. Suppose hehits the ball with a speed of 28 m/s at an angle of35o above the horizantal. (a) How long was the ball in flight? ____s (b) How far did it travel? ____m (c) How much faster would it have traveled on the moon than onearth? ____m
(a) How long was the ball in flight? ____s (b) How far did it travel? ____m (c) How much faster would it have traveled on the moon than onearth? ____m

Explanation / Answer

   Acceleration due to gravity onmoon   gm   =   g/6   =   9.8/6   =   1.633   m/s2    a.   Time offlight   T   =   2* u * sin /gm   =   2 * 28 * sin350 /1.633   =   19.67   s    b.   Maximum distance (rage)   Rmoon   =   u2* sin 2 / gm   =   282* sin (2 * 350) / 1.633   Rmoon   =   451.14   m    c.   Please clarify what youmean by faster, or is it farther.    Rearth   =    u2* sin 2 /g   =   282 *sin (2 * 350) /9.8   =   75.17   m    Distancedifference      R   =   Rmoon   -   Rearth   =   451.14   -   75.17   =   375.97   m    i.e. the golf ball would travel375.97   m farther on moon than on earth.            a.   Time offlight   T   =   2* u * sin /gm   =   2 * 28 * sin350 /1.633   =   19.67   s    b.   Maximum distance (rage)   Rmoon   =   u2* sin 2 / gm   =   282* sin (2 * 350) / 1.633   Rmoon   =   451.14   m    c.   Please clarify what youmean by faster, or is it farther.    Rearth   =    u2* sin 2 /g   =   282 *sin (2 * 350) /9.8   =   75.17   m    Distancedifference      R   =   Rmoon   -   Rearth   =   451.14   -   75.17   =   375.97   m    i.e. the golf ball would travel375.97   m farther on moon than on earth.        

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