the free body diagram of an 8 kg FIGURE 4-11 50NAy 11) The free-body diagram of

Question

the free body diagram of an 8 kg FIGURE 4-11 50NAy 11) The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law 11) for this object? A) (6.0 N cos 285.0 N sin 22)i (60 N sin 28- 5.0 N cos 22)- (8.00 kg) a A) (6.0 N cos 28" + 5.0 N sin 22")1+ (6.0 N sin 28. 5.0 N cos 22)-(8.00 kg) a B) (6.0 N cos 28"-5.0 N sin 22")1+ (6.0 N sin 28" + 5.0 N cos 22")-(8.00 kg) a ON cos 28°-5.0 N cos 22")1+ (6.0 N sin 28" + 5.0 N sin 22.)js (8.00 kg) a D) (60N sin 28-5.0 N sin 22 )1 (60 N cos 28+50 N cos 22-(8.00 kg) a E) (6.0 Ncos 28" + 5.0 N cos 227-(6.0 N sin 28" + 5.0 N sin 22")-(8.00 kg) a 2) A 4,00-kg block slides down a frictionless inclined plane with an acceleration 3.00 m/s2, What is 1 the angle of the incline above horizontal

Explanation / Answer

here,

11)

for the free body diagram

mass , m =8 kg

using Newton's seccond law

( 6 N * cos(28) - 5 N * cos(22)) + ( 6 N * sin(28) + 5 N * sin(22)) = 8 * a

so the correct option is C)

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