Using the follow data table below for the Earth and vVenus to solve the floowing
ID: 3280406 • Letter: U
Question
Using the follow data table below for the Earth and vVenus to solve the floowing problems.
*Note: This value already takes into account the amount reflected off the clouds so this the effective amount actually absorbed from the sun each day and thus no further correction for albedo ir required.
(1). Find the average surface temperature for venus and earth that you would expect based on the balance of energy flux at equilibrium using the stephan-Boltzmann law assuming an emissivity of 1.0.
(2). Find the total amount of power the atmosphere of each planet must absorb per day in order to maintian the actual average surface temperature that is observed?
(3). Based on the average solar irradiance absorbed by the atmosphere given in the teble as well as the answer you found in part (2), give two important differences between the atmosphere on earth and on venus implied by this data.
Avg. distance to sun (km). Avg solar Irradiance absorbed bt Atm. (W/m^2/day)* Avg. radius of planet & Atm (km) Avg surface temperature (K) Venus 108,208,000 163 6,102 735 Earth 149,598,261 237 6,421 388Explanation / Answer
1. for venus
given, sollar irradiance absorbed per day, L = 163 W/m^2
let average surface temperature for a day be T
then from stefans - boltzmann law
L = sigma*T^4
wheere sigma is stefan's constat, sigma = 5.67*10^-8
163 = 5.67*10^-8*T^4
T = 231.553 K
similiarly for earth
L = 237
237 = 5.67*10^-8*T^4
T = 254.267 K
2. for venum, power to be absorbed per day = P
P = sigma*AT^4
A = pi*r^2
r = 6102,000 m
T = 735 K
so, P = 1.935*10^18 W/day
for earth
r = 6421,000 m
T = 388 K
P = 5.67*10^-8*pi*r^2*T^4
P = 0.1664*10^18 W/day
3. hence, based on the two parts before and the table
Venus absorbs more radiation than earth from sun, and doesnot reflect much of it back
and the albedo of venus is more than that of earth
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.