d/3 d/3 K2 d/3 k1 4. Cecil is the slowest eater of the pack. The other two often
ID: 3280239 • Letter: D
Question
Explanation / Answer
a)The potential due to 50 uC of charge at 0.5 m will be:
V = k q/r = 9 x 10^9 x 50 x 10^-6/0.5 = 9 x 10^5 V
Work done is:
W = U = q V
W = 50 x 10^-6 x 9 x 10^5 = 45 J
Hence, W = 45 J
b)This work will be equal to the potential energy of the configuration
since, there is no charge on Cecil, q1 = 0
q2 = q3 = 50 uC
U = k/r (q1q2 + q2q3 + q3q1) = 9 x 10^9/0.5(0 + 50 x 50 x 10^-12 + 0 ) = 45 J
Hence, U = 45 J
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.