16. 120 points OSColPhys1 2.5.034.XP My Notes Ask Your Teacher An express subway

Question

16. 120 points OSColPhys1 2.5.034.XP My Notes Ask Your Teacher An express subway train passes through an underground station. It enters at t = 0 with an initial velocity of 22.0 m/s and decelerates at a rate of 0.150 m/s2 as it goes through. The station in 200 m long. (a) How long is the nose of the train in the station? (b) How fast is it going when the nose leaves the station? (c) If the train is 130 m long, at what time t does the end of the train m/s leave the station? (d) What is the velocity of the end of the train as it leaves? m/s

Explanation / Answer

A) using the second equation of motion,

s = ut +0.5at^2

200 = 22t - 0.5*0.15 t^2

t = 9.39 s answer

B) Using first equation of motion,

v = u +at

= 22 - 0.15*9.39

= 20.59 m/s answer

C) again using the second equation of motion,

200 +130 = 22t - 0.5*0.15 t^2

t = 15.857 s answer

D) v = u +at

= 22 - 0.15*15.857

= 19.6 m/s answer

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