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Sign in or Sign Up I Chegg.cem College Physics I (1401) Grace Period: 8 days lef

ID: 3279910 • Letter: S

Question

Sign in or Sign Up I Chegg.cem College Physics I (1401) Grace Period: 8 days left Register Now Cutnell, Physics, 10e Gradebook ORION Downieadable eTextbook Focus on Concepts, Question 23 A boy jumps trom rest, straight down from the top of a ci. He fails haltway down to the water below in 0.953 s. How much time passes curing his entire trip from the top to the water? Ignore air resistance. the tolerance is +/-2% Click if you would Wihe to Show Work for this question! Osen Sho wor 0 of 3 used saut rom La - MacBook Ait 8

Explanation / Answer

Given,

t = 0.953 s ; its the time taken to cover the half distance.

We know that,

S = ut + 1/2 at^2

h = 0 + 0.5 x 9.81 x .953^2 = 4.45 m

H = 2h

H = 2 x 4.45 = 8.9 m

using the same eqn,

H = 1/2 g t^2

t = sqrt (2H/g) = sqrt (2 x 8.9/9.81) = 1.35 s

Hence, T = 1.35 s

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