time=5×10^-9seconds is the correct answer please show the work considering force

Question

time=5×10^-9seconds is the correct answer
please show the work considering force acting on the charged particle.

e=1.6 x 10-15 c m-9.1X1o 1 kg An electron is projected horizontally into the uniform electric field E-400 N/C directed vertically downward between two parallel plates as shown in the figure. The plates are 2 m apart and are of length 4 m. The initial velocity of this electron is w - 8 x 101 m/'s to the right (positive x-direction). Vi W = 2m L = 4m 1. The two parallel plates in the above fgure are oppositely charged metallic plates. Which one (upper or lower onel is positively electron passes through the chamber without coliding into ether of the conducting plates. What is the time the elect spends between the plates? 2 The +5x10 econds

Explanation / Answer

1] upper one is positively charged as electric field lines comes out of positive charge into negative charge.

2] Horizontal component of the velocity is uneffected by the field. The electric force acts only in vertical direction (on electron it acts upward), so it changes only vertical component of the velocity, not horizontal. Path will be parabolic.

time t = time required to pass the horizontal distance of L

time t = L/v

= 4m /[8*10^8 m/s]

= 5*10^-9 s answer

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