A heavy electric motor is to be carried by two men by placing it on a board 2.0

Question

A heavy electric motor is to be carried by two men by placing it on a board 2.0 m long and weight 200N. To lift the board with the motor on it, one man must lift one end with a force of 600N and the opposite end with a force of 400N. What is the weight of the motor and where is it located? A heavy electric motor is to be carried by two men by placing it on a board 2.0 m long and weight 200N. To lift the board with the motor on it, one man must lift one end with a force of 600N and the opposite end with a force of 400N. What is the weight of the motor and where is it located?

Explanation / Answer

l = 2 m ; w = 200 N ; f1 = 600 N ; f2 = 400 N

Let W be the motors weight. W will be given by

W = f1 + f2

W = 600 + 400 = 1000 N

Hence, W = 1000 N

Let x, be the distance of motor from man who exerts f1= 400 N. then the distance of f2 application will be (2 - x)

Considering sum of torques,

400 x = 600 (2 - x)

4 x = 12 - 6x

x(4 + 6) = 12 => x = 12/10 = 1.2 m

Hence, x = 1.2 m

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