1) What is the best value of f (av) ± f (av) obtained by averaging all the data.

Question

1) What is the best value of f (av) ± f (av) obtained by averaging all the data. f (av) is an overall error in your set of data for f. (Show calculations)

2) see below

3) see below

4) see below

Data needed to answer questions is below

Image Formation Analysis Refer to the data taken with the optical bench set-up. (1) what is the best value of f (av)s df(av) obtained by averaging all the data. f(av) is an overall error in your set of data for f. Show calculations. (2) Do all your values of d, and d, yield comparable values of f within the experimental error? Explain with reference to your data (3) What is the value of f for the lens you used? [See the label on the lens.] Does your value of f agree with the expected value or not? Explain. difference between the expected and the experimental values? What is the percent (4) Refer to the graphs and answer the following questions. (a) Refer to your graph of d, versus d, Does increasing the object distance always decrease the image distance? Support your answer with numbers from your data.

Explanation / Answer

1. 1) After entering the data in excel we get

Fav = 10.45 cm

d(Fav) = 0.084984 cm

so, the final result can be represented as

fav = 10.45 +- 0.084984 cm

here 10.45 is mean of all the readins

d(Fav) is the standard deviation in the values of Fav

2) all the values of di and do give the f values that are real close to the experimental average value obtained in the experiment.

3) the expected value of f for the lens is 10 cm ( as given )

so percentage error in the experimental reading is

(10.45 - 10)*100/10 = 4.5 percentage

4) yes, as we can see from the graph, increassing object distance always decreases image distance, no exceptions

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.