0.43 is a good estimate of a, how A standard method for the determination of glu

Question

0.43 is a good estimate of a, how A standard method for the determination of glucose in serum is reported to have a standard deviation of 0.43 mg/dL. Ifs many replicate determinations should be made in order for the mean for the analysis of a sample to be within (This problem requires values in your textbook's specific appendices, which you can access through the OWLv2 MindTap Reader. You should not use the OWLv2 References' Tables to answer this question as the values will not match.) Remember that you always need to round your final answer up to a whole number of replicates a 0.3 mg/dL of the true mean 99% of the time? Na b. 0.3 mg/dL of the true mean 95% of the time? 0.2 mg/dL of the true mean 90% of the time? Try Another Verslon 10 item attempts remaining

Explanation / Answer

n = z(a/2)^2*Sd^2/ME^2 a) alpha 0.01 z(a/2) 2.575829304 SD 0.43 ME 0.3 n= =2.576^2*0.43^2/0.3^2 13.63102646 14 b) alpha 0.05 z(a/2) 1.959963985 SD 0.43 ME 0.3 n= =1.96^2*0.43^2/0.3^2 7.892063733 8 c) alpha 0.1 z(a/2) 1.644853627 SD 0.43 ME 0.2 n= =1.645^2*0.43^2/0.2^2 12.50637462 13

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