In a multiple comparison test for mu_2 - mu_4, the Fisher\'s 95% confidence inte

Question

In a multiple comparison test for mu_2 - mu_4, the Fisher's 95% confidence interval is calculated as (-11.29, -2.75). What is the conclusion under the Fisher's method? A. Do not reject H_0 and conclude that population means mu_2 and mu_4 are significantly different B. Reject H_0 and conclude that population means mu_2 and mu_4 are significantly different C. Reject H_0 and conclude that population mu 2 and mu 4, are nor significantly different D. Do not reject H_0 and conclude that population means mu 2 and mu 4 are not significantly different For a two-way ANOVA without interaction, it is calculated that = 15, r = 4, c = 5, SST = 260, SSA = 15, SSB = 196.

Explanation / Answer

95% confidence interval is, (-11.29 , -2.75 )

optiob B] Reject H0 , and conclude that the population mean mu2 and mu4 are significantly different.

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