Professor Cramer determines a final grade based on attendance, two papers, three

Question

Professor Cramer determines a final grade based on attendance, two papers, three major tests, and a final exam. Each of these activities has a total of 100 possible points. However, the activities carry different weights. Attendance Is worth 6%, each paper is worth 6%, each test is worth 17%, and the final is worth 31%. (a) What is the average for a student with 91 on attendance, 73 on the first paper, 72 on the second paper, 94 on test 1, 98 on test 2, 82 on test 3, and 99 on the final exam? (b) Compute the average for a student with the above scores on the papers, tests, and final exam, but with a score of only 23 on attendance.

Explanation / Answer

a) The weighted score is computed by multiplying the various scores with their corresponding weights. Therefore the weighted score here is obtained as:

= 91*0.06 + 73*0.06 + 72*0.06 + 94*0.17 + 98*0.17 + 82*0.17 + 99*0.31

= 91.43

Therefore the weighted score here is 91.4 ( rounded to one decimal place )

b) Similar to previous part, here the weighted score would be:

= 23*0.06 + 73*0.06 + 72*0.06 + 94*0.17 + 98*0.17 + 82*0.17 + 99*0.31

= 87.35

Therefore the weighted score here is 87.4 ( rounded to one decimal place )

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