MY QUESTION IS WHAT TABLE DO YOU USE TO FIND 2.086????????? Assuming that both p

Question

MY QUESTION IS WHAT TABLE DO YOU USE TO FIND 2.086?????????

Assuming that both populations are normally distributed, construct a 95% confidence interval about mu_1 - mu_2middot (mu_1 represents the mean of the experimental group and mu_2 represents the mean of the control x group.) To construct a confidence interval about the difference of two independent means, the following can be used to approximate the bounds. Use the smaller of n_1 - 1 and n_2 -1 degrees of freedom. Lower bound: Lower bound: (x bar_1 - x bar_2) - t_alpha/2 middot squareroot s^2_1/n_1 + s^2_2/n_2 Upper bound: (x bar_1 - x bar_2) + t_alpha/2 middot squareroot s^2_1/n_1 + s^2_2/n_2 The degrees of freedom for Student's t-distribution can be approximated by the smaller of n_1 - 1 and n_2 - 1. In this case there are 20 degrees of freedom. Then find the value of t_alpha/2 = t_0.025 for 20 degrees of freedom. Use a table to find the value of t so that the area to the right is 0.025. t_0.025 almostequalto 2.086 Substitute the known values into each formula to find the bounds, First compute the lower bound.

Explanation / Answer

We find t-critical values from a t-table. You can find any t-table from a websearch, following is just one such website:

http://www.sjsu.edu/faculty/gerstman/StatPrimer/t-table.pdf

Look for row with df = 20, go across right and under the column heading of "0.025" (for one-tail), and you will find 2.086.

This means that t (with df = 20) has has area of 0.025 on right of 2.086

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