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The 2 pictures below is the same problem with the chart The 2 pictures below is

ID: 3263467 • Letter: T

Question




The 2 pictures below is the same problem with the chart



The 2 pictures below is the same problem with the chart



Homework: WS 4 Homework Problems Save Score: 2.4 of 6 pts 6 of 10 (10 complete) HW Score: 60.26%, 36.16 of 60 pts 9.2.26-T Question Help A marketing researcher wants to estimate the mean savings (S) realized by shoppers who showroom Showrooming is the practice of inspecting products in retail stores and then purchasing the products online at a lower price. A random sample of 150 shoppers who recently purchased a consumer electronics item online after making a visit to a retail store y standard deviation of $54. Complete parts (a) and (b) below online after making a visit to a retail store yielded a mean savings of $57 and a elded a mean savings of ss a. Is there evidence that the population mean savings for all showroomers who purchased a consumer electronics item is different from $53? (Use a 0.10 level of significance) State the null and alternative hypotheses Type integers or decimals. Do not round Do not include the S symbol in your answer) Identify the critical value(s) The critical value(s) is(are) (Type an integer or a decimal. Round to two decimal places as needed. Use a comma to separate answers as needed.) Enter your answer in the answer box and then click Check Answer Chock Answe 4 pertaining parts remaining 5:42 PM , o ide) 7/17/2017 a 0 Type here to search

Explanation / Answer

Answer:

Q6).

Critical values =(-1.66, 1.66)

Test statistic = 0.907

Ho is not rejected.

t Test for Hypothesis of the Mean

Data

Null Hypothesis                m=

53

Level of Significance

0.1

Sample Size

150

Sample Mean

57

Sample Standard Deviation

54

Intermediate Calculations

Standard Error of the Mean

4.4091

Degrees of Freedom

149

t Test Statistic

0.9072

Two-Tail Test

Lower Critical Value

-1.6551

Upper Critical Value

1.6551

p-Value

0.3658

Do not reject the null hypothesis

Q7).

Test statistic = -2.09

Critical value = -1.65

Ho is rejected.

t Test for Hypothesis of the Mean

Data

Null Hypothesis                m=

25

Level of Significance

0.05

Sample Size

341

Sample Mean

23.16

Sample Standard Deviation

16.29

Intermediate Calculations

Standard Error of the Mean

0.8822

Degrees of Freedom

340

t Test Statistic

-2.0858

Lower-Tail Test

Lower Critical Value

-1.6493

p-Value

0.0189

Reject the null hypothesis

Q8).

Z stat= -0.58

Critical values =(-2.576, 2.576)

Ho is not rejected.

Z Test of Hypothesis for the Proportion

Data

Null Hypothesis            p =

0.51

Level of Significance

0.01

Number of Items of Interest

7

Sample Size

16

Intermediate Calculations

Sample Proportion

0.4375

Standard Error

0.1250

Z Test Statistic

-0.5801

Two-Tail Test

Lower Critical Value

-2.5758

Upper Critical Value

2.5758

p-Value

0.5618

Do not reject the null hypothesis

Q9).

t stat= -0.93

Pooled-Variance t Test for the Difference Between Two Means

(assumes equal population variances)

Data

Hypothesized Difference

0

Level of Significance

0.05

Population 1 Sample

Sample Size

20

Sample Mean

28

Sample Standard Deviation

24.89134282

Population 2 Sample

Sample Size

20

Sample Mean

36.7

Sample Standard Deviation

33.47599297

Intermediate Calculations

Population 1 Sample Degrees of Freedom

19

Population 2 Sample Degrees of Freedom

19

Total Degrees of Freedom

38

Pooled Variance

870.1105

Standard Error

9.3280

Difference in Sample Means

-8.7000

t Test Statistic

-0.9327

Two-Tail Test

Lower Critical Value

-2.0244

Upper Critical Value

2.0244

p-Value

0.3569

Do not reject the null hypothesis

t Test for Hypothesis of the Mean

Data

Null Hypothesis                m=

53

Level of Significance

0.1

Sample Size

150

Sample Mean

57

Sample Standard Deviation

54

Intermediate Calculations

Standard Error of the Mean

4.4091

Degrees of Freedom

149

t Test Statistic

0.9072

Two-Tail Test

Lower Critical Value

-1.6551

Upper Critical Value

1.6551

p-Value

0.3658

Do not reject the null hypothesis