The 2 nd Practice Problem : A 3.0 m uniform rod weighing 12 N is suspended horiz

Question

The 2nd Practice Problem: A 3.0 m uniform rod weighing 12 N is suspended horizontally from a wall by a hinge and wire arrangement as shown in the drawing below. At the end of the rod a 25 N sign is hung. The wire makes an angle of q = 280 with the rod. The arrangement is completely static. Determine the tension on the wire and both the x and y forces from the wall on the hinge. Be certain to draw a comprehensive free body diagram and indicate your choice of axis of rotation (pivot point).

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Explanation / Answer

Place the pivot point at the hinge and go about the x axis to balance the torques

(12)(1.5) + (25)(3) = T(sin 28)(3)

T = 66.0 N

Then the y component of the hinge is Fy + 66(sin 28) = 12 + 25

Fy = 6.01 N

Fx = 66cos(28)

Fx = 58.3 N

These answer are based on the assumption that the wire is at the end of the rod where the sign is. If that is not the case, ask questions BEFORE you rate and we can work this out. Since it wasn't stated where the wire is attached, and the figure is not included, I just made the assumption. Remember, ask BEFORE you rate if needed. Thanks!

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