Samples of pages were randomly selected from three different novels. The Flesch

Question

Samples of pages were randomly selected from three different novels. The Flesch Reading Ease scores were obtained from each page, and the TI-83/84 Plus calculator results from analysis of variance are given below. Use a 0.05 significance level to test the claim that the three books have the same mean Flesch Reading Ease score. 1 Click the icon to view the T-83/84 Plus calculator results. Click the icon to view the TI-83/84 Plus calculator results. What is the conclusion for this hypothesis test? OA. Fail to reject Ho. There is sufficient evidence to warrant the rejection of the claim that the three books have the same mean Flesch Reading Ease score. O B. Fail to reject Ho. There is insufficient evidence to warrant the rejection of the claim that the three books have the same mean Flesch Reading Ease score. OC. Reject Ho- There is sufficient evidence to warrant rejection of the claim that the three books have the same mean Flesch Reading Ease score. 0 D. Reject Ho-There is insufficient evidence to warrant the rejection of the claim that the three books have the same mean Flesch Reading Ease score

Explanation / Answer

The null hypothesis states that the population means are all equal.

From F table with df1 = 2 and df2 = 32 we found:

Critical F value = 3.29

An F statistic is a value you get when you run an ANOVA test or a regression analysis to find out if the means between two populations are significantly different.

A small p-value (typically 0.05) indicates strong evidence against the null hypothesis, so you reject the null hypothesis.

Here, F>Fcritical thus also, we reject null so, means not equal.

C option is the answer.

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