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A machine that is programmed to package 1.20 pounds of cereal is being tested fo

ID: 3257692 • Letter: A

Question

A machine that is programmed to package 1.20 pounds of cereal is being tested for its accuracy. In a sample of 36 cereal boxes, the sample mean filling weight is calculated as 1.22 pounds. The population standard deviation is known to be 0.06 pound. Use Table 1. a-1. Identify the relevant parameter of interest for these quantitative data. The parameter of interest is the average filling weight of all cereal packages. The parameter of interest is the proportion filling weight of all cereal packages. a-2. Compute its point estimate as well as the margin of error with 95% confidence. (Round intermediate calculations to 4 decimal places. Round "z-value" and final answers to 2 decimal places.) Point estimate Margin of error b-1. Calculate the 95% confidence interval. (Use rounded margin of error. Round your answers to 2 decimal places.) b-2. Can we conclude that the packaging machine is operating improperly? Yes, since the confidence interval contains the target filling weight of 1.20. Yes, since the confidence interval does not contain the target filling weight of 1.20. No, since the confidence interval contains the target filling weight of 1.20. No, since the confidence interval does not contain the target filling weight of 1.20. c. How large a sample must we take if we want the margin of error to be at most 0.01 pound with 95% confidence? (Round "z-value" to 2 decimal places and round up your final answer to the next whole number.)

Explanation / Answer

Solution:-

a-1).

The parameter of interest is the average filling weight of all cereal packages.

a-2).

Point estimate = 0.0783

Margin of error = 16.3%

b-1).

95% Confidence Interval = 1.22 ± 0.02
= (1.20 to 1.24)

b-2).

Yes. Because the confidence interval contains the target filling weight of 1.20.

c).

Sample size = 6489

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