Of all murder victoms in 2010 whose relation to the offender was known, 28.8% we

Question

Of all murder victoms in 2010 whose relation to the offender was known, 28.8% were killed by a family member and 53% by an acquaintance. The rest were killed by a stranger. What is the probability that a randomly selected murder victom was killed by a stranger?

In a recent survey, 15 people preferred milk, 27 people preferred coffee and 18 people preferred juice as their primary drink for breakfast. If a person is sellected at random, find the probability that the person preferred juice as their primary drink.

Thanks for the help!!!

Explanation / Answer

1) We have,

               P(Family member) = 0.288                         P(acquaintance) = 0.53

Consider,

                 P(Family member) + P(acquaintance) + P(Stranger) = 1

                   0.288 + 0.53 + P(Stranger) = 1

                     0.818 + P(Stranger) = 1

                         P(Stranger) = 1 - 0.818

                        P(Stranger) = 0.182

Hence, The probability that a randomly selected murder victom was killed by a stranger is ; 0.182.

2) We have,

             N = 15 + 27 + 18 = 60 peoples.

              x = 18 preferred jiuce.

By definition of probability,

              P(preferred juice) = x/n = 18/60 = 0.3

Hence, The probability that the person preferred juice as their primary drink is : 0.30.

Related Questions

Navigate

• Browse (All)
• Browse O
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.