Suppose that we want to compare the cleansing action of three detergents on the
ID: 3249465 • Letter: S
Question
Suppose that we want to compare the cleansing action of three detergents on the basis of the following whiteness readings made on 15 swatches of white cloth, which were first soiled with India ink and then washed in an agitator-type machine with the respective detergents: Detergent A: 77 81 71 76 80 Detergent B: 72 58 74 66 70 Detergent C: 76 85 82 77 80 The means of these three samples are 77, 68, and 80, determine whether the differences among them are significant for alpha = 0.01. Use Tukey's test at alpha = 0.02 to determine the nature of the differences among treatment means.Explanation / Answer
Answer:
H_0: mu_1 = mu_2= mu_3
H1: At least one pair of population means are different
Table value of F with (DF1=2, DF2=12 ) at 0.01 level =6.93
Calculated F=8.48 >6.93 the table value
The null hypothesis is rejected.
The data indicate there is a significant difference among the three groups
One-way ANOVA: A, B, C
Method
Null hypothesis All means are equal
Alternative hypothesis At least one mean is different
Significance level = 0.05
Equal variances were assumed for the analysis.
Factor Information
Factor Levels Values
Factor 3 A, B, C
Analysis of Variance
Source DF Adj SS Adj MS F-Value P-Value
Factor 2 390.0 195.00 8.48 0.005
Error 12 276.0 23.00
Total 14 666.0
Model Summary
S R-sq R-sq(adj) R-sq(pred)
4.79583 58.56% 51.65% 35.25%
Means
Factor N Mean StDev 95% CI
A 5 77.00 3.94 (72.33, 81.67)
B 5 68.00 6.32 (63.33, 72.67)
C 5 80.00 3.67 (75.33, 84.67)
Pooled StDev = 4.79583
Tukey Pairwise Comparisons
Grouping Information Using the Tukey Method and 98% Confidence
Factor N Mean Grouping
C 5 80.00 A
A 5 77.00 A B
B 5 68.00 B
Means that do not share a letter are significantly different.
Tukey Simultaneous Tests for Differences of Means
Difference Difference SE of Adjusted
of Levels of Means Difference 98% CI T-Value P-Value
B - A -9.00 3.03 (-18.65, 0.65) -2.97 0.029
C - A 3.00 3.03 ( -6.65, 12.65) 0.99 0.597
C - B 12.00 3.03 ( 2.35, 21.65) 3.96 0.005
Individual confidence level = 99.21%
b).
Tukey test shows that detergent B and C are significant at 0.02 level significance.
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