In a test of the effectiveness of garlic for lowering cholesterol, 48 subjects w

Question

In a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes in their levels of LDL cholesterol (in mg/dL) have a mean of 3.6 and a standard deviation of 17.6. Complete parts (a) and (b) below. a. What is the best point estimate of the population mean net change in LDL cholesterol after the garlic treatment? The best point estimate is mg/dL (Type an integer or a decimal) b. Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? What is the confidence interval estimate of the population mean mu? mg/dL

Explanation / Answer

a)the best point estimate of the population mean net change in LDL cholesterol the garlic treatment the best point estimate is 3.6 mg/dL

b).95% confidence interval =1-0.95

=0.05

Level of significance =0.05

z =z/2 =1.96

ME =z* /sqrt(n)

=1.96*17.6 /sqrt(48)

= 4.98

95% confidence interval =(x^bar – ME)< < (x^bar + ME)

                                    =(3.6+4.98) < < (3.6+4.98)

                                    = -3.8 < < 8.58

                                    =-3.8 mg/dL < < 8.58 mg/dL

Confident interval contain zero suggest that the garlic treatment did not effect the LDL cholesterol levels.

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