In a television set, electrons are accelerated from restthrough a potential diff

Question

In a television set, electrons are accelerated from restthrough a potential difference of 22 kV. The electrons thenpass through a 0.26-T magnetic field that is perpendicular to thepath of the electrons, which deflects them through a circular arcto the appropriate spot on the screen. a) Find the magnitude of the maximum magnetic force thatan electron can experience b) Find the radius of the path that the electron takes in thismagnetic field. In a television set, electrons are accelerated from restthrough a potential difference of 22 kV. The electrons thenpass through a 0.26-T magnetic field that is perpendicular to thepath of the electrons, which deflects them through a circular arcto the appropriate spot on the screen. a) Find the magnitude of the maximum magnetic force thatan electron can experience b) Find the radius of the path that the electron takes in thismagnetic field.

Explanation / Answer

After the electrons are accelerated through the 22kVpotential of the electric field, they have a kinetic energy of 22kV.               ( 1 /2) mv2   = 22 k V    where m = mass of electron = 9.1*10-31 kg                             1 k V = 1.6*10-16 J ( 1/2) ( 9.1*10-31 kg )v2   =22*1.6*10-16 J                                      v   = 77.362*10 14                  velocity of electron = 8.79*107 m/s                   charge on electron    q = 1.6*10-19C       angle between field andelectron = 90 o    magnetic force that an electron can experience   F = B q V sin                = ........N             we know that     F = m v2 / r    radius of the path     r =mv2 / F                                    = ................ m plug the values and get the answers

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