Samples of pages were randomly selected from three different novels. The Flesch

Question

Samples of pages were randomly selected from three different novels. The Flesch Reading Ease scores were obtained from each page, and the TI-83/84 Plus calculator results from analysis of variance are given below. Use a 0.05 significance level to test the claim that the three books have the same mean Flesch Reading Ease score. 1 Click the icon to view the T-83/84 Plus calculator results. Click the icon to view the TI-83/84 Plus calculator results. What is the conclusion for this hypothesis test? OA. Fail to reject Ho. There is sufficient evidence to warrant the rejection of the claim that the three books have the same mean Flesch Reading Ease score. O B. Fail to reject Ho. There is insufficient evidence to warrant the rejection of the claim that the three books have the same mean Flesch Reading Ease score. OC. Reject Ho- There is sufficient evidence to warrant rejection of the claim that the three books have the same mean Flesch Reading Ease score. 0 D. Reject Ho-There is insufficient evidence to warrant the rejection of the claim that the three books have the same mean Flesch Reading Ease score

Explanation / Answer

From the given results, we have Fcalculated= MST/MSE= 686.620535 / 71.1506599= 9.6502342534

The critical value is given by Fk-1,n-k(0.05/2)= F2,32(0.025)= 4.149 (From probability tables)

Now since Fcalculated > 4.149, we have sufficient evidence to reject null hypothesis that the 3 books have same mean Flesch Reading ease score.

Hence we say the 3 books do not have same mean Flesch Reading ease score.

Thus option C is correct.

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